The period of oscillation of a simple pendulum is given by 
where l is about 100 cm and is known to have 1 mm accuracy. The period is about 2 s . The time of 100 oscillations is measured by a stop watch of least count 0.1 s. The percentage error in g is
Text Solution
Verified by ExpertsThe correct answer is:
C
Here % error in l = 
and % error in T = 
\ \ % error in g = % error in l + 2(% error in T )
= 0.2 %
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
The percentage errors in the measurement of mass and speed are 2% and 3% respectively. How much wil…
The random error in the arithmetic mean of 100 observations is x ; then random error in the arithme…
Error in the measurement of radius of a sphere is 1%. The error in the calculated value of its volu…
The mean time period of second 's pendulum is 2.00 s and mean absolute error in the time period is …
A body travels uniformly a distance of (13.8 ± ± 0.2) m in a time (4.0 ± ± 0.3) s. The velocity of …
The percentage error in the above problem is